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Proportions in similar triangles

Proportions in similar triangles-example-1
User Sharchaea
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1 Answer

5 votes

Answer:

x = 4

Explanation:

Given that DE is parallel to AC then DE divides the sides proportionally, so


(BD)/(DA) =
(BE)/(EC) , substitute values


(x+2)/(x) =
(3)/(2) ( cross- multiply )

3x = 2(x + 2) ← distribute

3x = 2x + 4 ( subtract 2x from both sides )

x = 4

User Robin C Samuel
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4.9k points