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Given: sin(theta)=3/5 and cos x = -12/3 ; evaluate the following expression. (theta: Quadrant I, x : Quadrant II.) sin( theta+ x ) -16/65 -33/65 -56/65
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Given: sin(theta)=3/5 and cos x = -12/3 ; evaluate the following expression.

(theta: Quadrant I, x : Quadrant II.)
sin( theta+ x )

-16/65
-33/65
-56/65

Given: sin(theta)=3/5 and cos x = -12/3 ; evaluate the following expression. (theta-example-1
User CrushedPixel
by
3.6k points

1 Answer

4 votes

Explanation:

-16/33

is the answer

I just typed it in a calculator

User Yukio
by
4.0k points
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