Question

Which of the following equations shows an incorrect relationship between pressures given in

terms of different units?
A) 1.20 atm = 122 kPa
B) 152 mm Hg = 2.03 104 Pa
C) 0.760 atm = 578 mm Hg
D) 1.0 torr = 2.00 mm Hg
E) 1.00 atm = 760 torr

Answer 1

Answer: The correct option is Option D.

Step-by-step explanation:

Pressure is also a measurement that is expressed in various units. Some of the units are Torr, atm, psi, pascals, mmHg, kPa, and bar

The interconversion of these units are as such:

• For (A):

1 atm = 101.325 kPa

So, 1.20 atm =
`(101.325kPa)/(1atm)* 1.20atm=122kPa`

• For (B):

1 mmHg = 133.32 Pa

So, 152 mmHg =
`(133.32Pa)/(1mmHg)* 152mmHg=20264.64=2.03* 10^4Pa`

• For (C):

760 mmHg = 1 atm

So, 0.760 atm =
`(760 mmHg)/(1atm)* 0.760atm=578mmHg`

• For (D):

1 mmHg = 1 torr

So, 1.0 torr =
`(1 mmHg)/(1torr)* 1torr=1mmHg`

This is an incorrect relationship.

• For (E):

760 torr = 1 atm

Hence, the correct option is Option D.