Question

Calculate the number of moles of NaOH in an aqueous solution of 36 cm3 of 0.1 mol dm−3.

PLSS EXPLAIN WHAT YOU DO I DONT GET IT

Answer 1

Answer: The number of moles of NaOH is 0.0036 moles

Step-by-step explanation:

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

`\text{Molarity of solution}=\frac{\text{Moles of solute}* 1000}{ \text{Volume of solution (mL)}}` .....(1)

Given values:

Molarity of NaOH =
`0.1mol/dm^3=0.1mol/L` (Conversion factor:
`1L=1dm^3`

Volume of the solution =
`36cm^3=36 mL` (Conversion factor:
`1mL=1cm^3`

Putting values in equation 1, we get:

`0.1=\frac{\text{Moles of NaOH}* 1000}{36}\\\\\text{Moles of NaOH}=(0.1* 36)/(1000)=0.0036mol`

Hence, the number of moles of NaOH is 0.0036 moles