180k views
8 votes
Solve 3x^2-4x-1=0

Can someone please explain to me how it went from 4 +/- the square root of 28 to 4 +/- 2 multiplied by the square root of 7.

Solve 3x^2-4x-1=0 Can someone please explain to me how it went from 4 +/- the square-example-1

1 Answer

9 votes

square root of 28 is 2√7

√28 = √4 * √7 = 2√7

User Jignesh Thakker
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories