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Calculate the oxidation number of the central atom of FeSO4 7H2O​
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Calculate the oxidation number of the central atom of FeSO4 7H2O​

User Alex Gao
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Answer:


{ \tt{let \: the \: oxidation \: state \: be \: x}} \\ { \bf{x + sulphate \: ion+ water = overall \: charge}} \\ \\ \\ { \tt{x + ( - 2) + 0 = 0}} \\ \\ { \tt{x = + 2}} \\ { \tt{oxidation \: state = + 2}}

User Matt Andruff
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