Answer:
![(5x - 1)(3x - 1)(x + 2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/1jf6wwpjb63nmxjn4zke4qd0h6rk3llunk.png)
Explanation:
![(15 {x}^(3) + 22 {x}^(2) - 15x + 2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/8otrv7sleiyk3rgck3m9u1v9usx68p5jkn.png)
Apply Rational Root Theorem, our possible roots will be
plus or minus( 2/15, 2/5,2/3,2, 1/15,1/5,1/3,1).
I
I tried root -2 and it work so
If we apply synthetic dividon, we would be left with
![15 {x}^(2) - 8x + 1](https://img.qammunity.org/2022/formulas/mathematics/high-school/qooc15xcpllnsy7np4qau7mokcc9tila2k.png)
We can factor this regularly.
Apply AC method that a number
AC will multiply to 15 but add to -8.
The answer are -5 and -3 so we write this as
![15 {x}^(2) - 5x - 3x + 1](https://img.qammunity.org/2022/formulas/mathematics/high-school/fo3l5o7oameiepymju586p917ke8qy3oal.png)
Factor by grouping
![(15x {}^(2) - 5x) - (3x + 1)](https://img.qammunity.org/2022/formulas/mathematics/high-school/v33g7es8u9ht1io8cp5wuxa5uzjw0oga0q.png)
![5x(3x - 1) - 1(3x - 1)](https://img.qammunity.org/2022/formulas/mathematics/high-school/l9578833vinwjqw71ssoslistj7l1oqxa1.png)
So our factor are
![(5x - 1)(3x - 1)(x + 2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/1jf6wwpjb63nmxjn4zke4qd0h6rk3llunk.png)