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What is the area of a sector when 0=90° and r= 8/3?
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What is the area of a sector when 0=90° and r= 8/3?

What is the area of a sector when 0=90° and r= 8/3?-example-1
User Umut K
by
4.2k points

2 Answers

4 votes

Answer:

Answer:

16π/9

Step-by-step explanation:

the area of sector= ¼×π.r²

= ¼× π× (8/3)²

= ¼×64/9×π

= 16π/9

Explanation:

User Volkinc
by
3.5k points
6 votes

Answer:

16π/9

Explanation:

the area of sector= ¼×π.r²

= ¼× π× (8/3)²

= ¼×64/9×π

= 16π/9

User Effectica
by
3.8k points
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