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If xsquared+ysquared=57 , xy=3 . find the value of 3(x+y)squared

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Answer:

189

Explanation:

If you mean this, my answer is 3x63= 189


{x}^(2) + {y}^(2) = 57 \\ xy = 3


{x}^(2) + {y}^(2) + 2xy = 57 + 2 * 3


{(x + y)}^(2) = 63


3 {(x + y)}^(2) = 3 * 63 = 189

User Hili
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