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Write the equations of two lines passing through (4,8)

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Answer:

Two lines that pass through the point (4, 8) are y = 3·x - 4 and y = -5·x + 28

Explanation:

The equation of two lines that passes through the point (4, 8) are found using the general form of a straight line equation, y = m·x + c, where;

m = The slope of the line

c = The y-intercept

Therefore, two distinct line pass through a given point if they have a different slope, m, and a different y-intercept, c, as follows;

Fot the given point, the x-value = 4, and the y-value = 8, we get;

8 = m₁·4 + c₁...Line 1 and

8 = m₂·4 + c₂...Line 2

m₁ ≠ m₂

If we set m₁ = 3, for line 1, we get;

8 = 3 × 4 + c₁ = 8 = 12 + c₁

∴ c₁ = 8 - 12 = -4

c₁ = -4

The equation for Line 1 for all x and y-values, where, m₁ = 3, c₁ = -4, becomes;

y = 3·x - 4

The equation for Line 2 where m₂ = -5 for example, we have;

8 = -5 × 4 + c₂

∴ c₂ = 8 + 5 × 4 = 28

c₂ = 28

The general form for the equation for Line 2 becomes;

y = -5·x + 28

Therefore;

The equation of the two formed lines that pass through the point (4, 8) are;

y = 3·x - 4 and y = -5·x + 28

User Nithi
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