Question

a car mass 1500kg traveling at a uniform velocity of 30 m/s due east .the driver applies the brake to slow down the car to a velocity of 10 m/s east . what is the work done in slowing down the car ?

Answer 1

The work done in slowing down the car is -375,000 J.

Step-by-step explanation:

The work done in slowing down the car can be calculated using the work-energy theorem. The work done is equal to the change in kinetic energy. The initial kinetic energy of the car is given by 1/2 * mass * (initial velocity)^2, and the final kinetic energy is given by 1/2 * mass * (final velocity)^2. Therefore, the work done is equal to the difference in the two kinetic energies:

Work = 1/2 * mass * ((final velocity)^2 - (initial velocity)^2)

Plugging in the given values:

Work = 1/2 * 1500 kg * ((10 m/s)^2 - (30 m/s)^2)

Work = 1/2 * 1500 kg * (-500 m^2/s^2)

Work = -375,000 J

Answer 2

this is the answer