Answer:
![X= \left[\begin{array}{ccc}-4&1\\5&-1\\\end{array}\right] \left[\begin{array}{ccc}21\\20\\\end{array}\right] \\](https://img.qammunity.org/2022/formulas/mathematics/high-school/yt7l186jwgg5vci0gticsesvx3lcyx4swk.png)
Explanation:
Given the simultaneous equation
x+y=21
5x+4y=20
To write in matrix form, it must be in the form AX= b
X = A⁻¹b
A⁻¹ is the inverse of matrix A
A is a 2by2 matrix
X is the variables
b is a column matrix
The expression will therefore be written as;
![A=\left[\begin{array}{ccc}1&1\\5&4\\\end{array}\right] \\\\|A| = 1(4)- 5(1)\\|A| = 4-5\\|A| = -1\\A^(-1) = -\left[\begin{array}{ccc}4&-1\\-5&1\\\end{array}\right] \\\\A^(-1) = \left[\begin{array}{ccc}-4&1\\5&-1\\\end{array}\right] \\](https://img.qammunity.org/2022/formulas/mathematics/high-school/uz2kkwr78qnwbtvvxe3k4o1zqqspdqvbjo.png)
Hence the required product matrix that represent X is;
![X= \left[\begin{array}{ccc}-4&1\\5&-1\\\end{array}\right] \left[\begin{array}{ccc}21\\20\\\end{array}\right] \\](https://img.qammunity.org/2022/formulas/mathematics/high-school/yt7l186jwgg5vci0gticsesvx3lcyx4swk.png)