Answer:
The true statements are;
1) The center of the ellipse is at (-2, -5)
3) The covertices are at (-2, -4) and (-2, -6)
4) The distance between the center and each focus is 2·√6 units
Explanation:
The given graph of the ellipse gives;
1) The location of the center of the ellipse = (-2, -5)
2) The location of the vertices of the ellipse = (-7, -5) and (3, -5)
The distance between the center (-2, -5) and each vertex, d, is given as follows;
d = -2 - (-7) = 5 and d = 3 - (-2) = 5
Therefore, the distance between the center (-2, -5) and each vertex is 5 units
3) The location of the covertices, given in the diagram are (-2, -4), and (-2, -6)
4) The coordinates of the focus of an ellipse = h - c, k
c = √(a² + b²)
Where, for the given ellipse, h = -2, k = -5, c = √(5² - 1²) = √(24) = 2·√6
∴ The location of the focus of the ellipse = (-2 - 2·√6, -5)
The distance between the center and each focus, d = -2 - (-2 - 2·√6) = 2·√6
5) The x-coordinate of the directrices of the ellipse = ± a/e
Where; a = 5
b² = a²·(1 - e²)
∴ e² = 1 - b²/a² = 1 - 1/25 = 24/25
e = 2·√6/5
The directrices = -2 ± 5/(2·√6/5) ≈ -2 ± 5.1
The distance between the center and the directrices ≈ 5.1 units
Therefore, the directrices are vertical lines approximately 5.1 units from the center