Question

(x+1)^2 . (x^2+1) = 0

Answer 1

`x^4+2x^3+2x^2+2x+1`

Explanation:

Given that,

`(x+1)^2 . (x^2+1) = 0`

We know that,
`(a+b)^2=a^2+b^2+2ab`

So,

`(x+1)^2=x^2+1+2x`

So,

`(x+1)^2 . (x^2+1) = (x^2+1+2x)(x^2+1)\\\\=x^2* x^2+x^2+2x^3+x^2+1+2x\\\\=x^4+2x^3+2x^2+2x+1`

So, the value of the given expression is equal to
`x^4+2x^3+2x^2+2x+1`