Question

The probability distribution for a random variable x is given in the table X: -5,-3,-2,0,2,3 Probability: .17,.13,.33,.16,.11,.10 Find the probability that -2<_x<_2

Answer 1

0.6 probability that
`-2 \leq x \leq 2`

Explanation:

The probability distribution is given in the table.

Probability that x is between -2 and 2.

Between -2 and 2, inclusive, we have -2, 0 and 2. So

`P(-2 \leq x \leq 2) = P(X = -2) + P(X = 0) + P(X = 2)`

From the table:

`P(X = -2) = 0.33, P(X = 0) = 0.16, P(X = 2) = 0.11`. So

`P(-2 \leq x \leq 2) = P(X = -2) + P(X = 0) + P(X = 2) = 0.33 + 0.16 + 0.11 = 0.60`

0.6 probability that
`-2 \leq x \leq 2`