Question

PLEASE help! I really appreciate it thanks!

Answer 1

The answer is
`h=(A+-\pi r^(2) )/(2\pi r)`.

Explanation:

To solve for (h), start by subtracting (
`\pi r^(2)`) from both sides, and the equation will look like
`A-\pi r^(2)= 2\pi rh+\pi r^2-\pi r^2`. The next step is to simplify the equation, which will look like
`A-\pi r^(2) =2\pi rh`.

Next, divide both sides of the equation by
`2\pi r`, and it will look like
`(A-\pi r^(2) )/(2\pi r) =(2\pi rh)/(2\pi r)`. Finally, simplify the equation, and the answer will be
`h=(A+-\pi r^(2) )/(2\pi r)`.

Answer 2

h=A-πr²÷2πr

Explanation:

Making h subject

A=2πrh+πr²

A-πr²=2πrh

A-πr²÷2πr=h

h=A-πr²÷2πr