Question

Rewrite with only sin x and cos x.

sin 2x - cos x

Answer 1

2sinxcosx - cosx OR cosx(2sinx - 1)

Explanation:

Use the double angle identity for sin2x.

sin2x = 2sinxcosx

Substitute sin2x with 2sinxcosx.

2sinxcosx - cosx

Factor out cosx, if needed.

cosx * (2sinx - 1)

Answer 2

`{ \tt{ \sin2x - \cos x }} \\ = { \tt{(2 \sin x \cos x) - \cos x }} \\ = { \tt{ \cos x(2 \sin x - 1) }}`