11.9k views
2 votes
Rewrite with only sin x and cos x.

sin 2x - cos x

User Lisha
by
8.3k points

2 Answers

1 vote

Answer:

2sinxcosx - cosx OR cosx(2sinx - 1)

Explanation:

Use the double angle identity for sin2x.

sin2x = 2sinxcosx

Substitute sin2x with 2sinxcosx.

2sinxcosx - cosx

Factor out cosx, if needed.

cosx * (2sinx - 1)

User Logman
by
8.0k points
3 votes

Answer:


{ \tt{ \sin2x - \cos x }} \\ = { \tt{(2 \sin x \cos x) - \cos x }} \\ = { \tt{ \cos x(2 \sin x - 1) }}

User Cyntia
by
8.9k points

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