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2 votes
-4x^4 - 3x^3 - 29x^2 - 114 where x= -4

2 Answers

4 votes

Answer: -1410

Explanation:

Let's start by subbing in -4 for x


-4x^4 - 3x^3 - 29x^2 - 114\\-4(-4)^4-3(-4)^3-29(-4)^2-114

Now we can solve


-4(256)-3(-64)-29(16)-114\\-1024--192-464-114\\-832-464-114\\-1296-114\\-1410

User Kasur
by
2.9k points
2 votes

Answer:


-1440

Explanation:

------------------------------

Given:


-4x^4-3x^3-29x^2-114=


x=-4

--------------->>>>

Let's substitute
-4 for
x and solve


-4(-4)^4-3(-4)^3-29(-4)^2-144=

Multiply the exponents


-4(256)-3(-64)-29(16)-144=

Multiply the parenthesis


-1024+192-464-144=


-832-464-144=


-1296-144=


=-1440

------------------------------

Hope this helps.

User SlyChan
by
3.0k points