Question

SV is a midsegment of △RTU.
If TU=y+38 and SV=y–9, what is the value of y?

Answer 1

y = 56

Explanation:

the midsegment SV is half the length of the side TU , that is

y - 9 =
`(1)/(2)` (y + 38) ← multiply both sides by 2 to clear the fraction

2y - 18 = y + 38 ( subtract y from both sides )

y - 18 = 38 ( add 18 to both sides )

y = 56