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A businessman dropped a coin from the top floor of his office building and it fell according to the formula S(t)=−16t^2+2t^0.5, where t is the time in seconds and S(t) is the distance in feet from the top of the building. Step 1 of 3 : If the coin hit the ground in exactly 1.8 seconds, how high is the building? Round your answer to 2 decimal places.

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Answer:

The height of the building is of 48.24 feet.

Explanation:

Height after t seconds:

The height after t seconds of the coin is given by:


S(t) = -16t^2 + 2t + h

In which h is the height of the building.

If the coin hit the ground in exactly 1.8 seconds, how high is the building?

This means that when
t = 1.8, S(t) = 0. We use this to find h.


S(t) = -16t^2 + 2t + h


h = 16t^2 - 2t


h = 16(1.8)^2 - 2(1.8)


h = 48.24

The height of the building is of 48.24 feet.

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