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What is the solution to this equation? (1/4)^x+1 =32

Help ASAP What is the solution to this equation? (1/4)^x+1 =32-example-1
User WHITECOLOR
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Answer:

B.
\displaystyle (-7)/(2)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

Algebra I

  • Exponential Rule [Powering]:
    \displaystyle (b^m)^n = b^(m \cdot n)
  • Exponential Rule [Rewrite]:
    \displaystyle b^(-m) = (1)/(b^m)

Explanation:

Step 1: Define

Identify


\displaystyle \bigg( (1)/(4) \bigg)^(x + 1) = 32

Step 2: Solve for x

  1. Rewrite:
    \displaystyle \bigg( (1)/(2^2) \bigg)^(x + 1) = 2^5
  2. Exponential Rule [Rewrite]:
    \displaystyle (2^(-2))^(x + 1) = 2^5
  3. Exponential Rule [Powering]:
    \displaystyle 2^(-2(x + 1)) = 2^5
  4. Set:
    \displaystyle -2(x + 1)} = 5
  5. [Division Property of Equality] Divide -2 on both sides:
    \displaystyle x + 1 = (-5)/(2)
  6. [Subtraction Property of Equality] Subtract -1 on both sides:
    \displaystyle x = (-7)/(2)
User Manikanta
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