Question

Somebody please help asap

Answer 1

B.
`4x^2 + (3)/(2)x - 7`

Explanation:

`f(x) = (x)/(2) - 3`

`g(x) = 4x^2 + x - 4`

(f + g)(x) = f(x) - g(x)

=
`(x)/(2) - 3 + 4x^2 + x - 4`

Add like terms

`= 4x^2 + (x)/(2) + x - 3 - 4`

`= 4x^2 + (3x)/(2) - 7`

`= 4x^2 + (3)/(2)x - 7`