Question

ASAP need help confused

Answer 1

b =
`(3z + 6)/(3z+1)`

Explanation:

Simply solve for "b" , so the formula will be

b = .....

z =
`(-b+6)/(3b-3)` ( b > 0 )

z(3b - 3) = - b + 6

3zb - 3z = - b + 6

3zb + b = 3z + 6

b( 3z + 1 ) = 3z + 6

b =
`(3z + 6)/(3z+1)`

Answer 2

b= (3z-6)/(1+3z)

Explanation:

z=(-b+6)/(3b-3)

cross multiple

z(3b-3)=-b+6

open the bracket

3bz-3z=-b+6

make -b the subject of the formula

-b = 3bz-3z-6

-b - 3bz = -3z - 6

factorize the left hand side...

-b(1+3z) = -3z-6

make -b the subject of the formula again

-b = -(3z-6)/(1+3z)

cancel the minus at both sides...

b = (3z-6)/(1+3z)