43.4k views
5 votes
Determine the value of c that makes the function f(x y) = c/x-y/ a joint discrete probability density function for x=2,0,2 and y=-2,3

User Dennisg
by
7.8k points

1 Answer

1 vote

Given: The given function is


f(x,y)=c(x-y)

To find: Here we need to find the value of c for which f(x,y) will be a joint

discrete probability density function.

Solution:

Now, to find c we have,


\int\limits^3_(-2) \,\int\limits^2_0 {f(x,y)} \, dx dy\\=\int\limits^3_(-2) \,\int\limits^2_0 {c(x-y)} \, dx dy\\\\=\int\limits^3_(-2) \,[2c-2cy]dy\\=10c-5c\\=5c\\The integral should be1.\\So, 5c=1\\


c=(1)/(5)

Therefore, the required value of c is 1/5.

User Chae
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories