Question

1.What are the coordinates of the vertices of ABC? Use the coordinates to find the lengths of AC and AB .

2.Use the distance formula to find BC. Show your work.

Answer 1

The person above me has the correct answer and solves it in the correct way.

Explanation:

This is what I used as my answer though.

Distance Formula: d = √(x2-x1)^2 + (y2-y1)^2

BC = √(x2-x1)^2 + (y2-y1)^2

B = (6,2)

C = (2,-1)

BC = √(2-6)^2 + (-1-2)^2

BC = √(-4)^2 + (-3)^2

BC = √16+9

BC = √25

BC = 5

Answer 2

Answer/Step-by-step explanation:

1.

✔️Coordinates of vertices ABC:

A(2, 2)

B(6, 2)

C(2, -1)

✔️AC = |2 - (-1)| = 3 units

AB = |2 - 6| = 4 units

2. Distance formula =>
`d = √((x_2 - x_1)^2 + (y_2 - y_1)^2)`

Distance between B(6, 2) and C(2, -1):

`BC = √((x_2 - x_1)^2 + (y_2 - y_1)^2)`

Where,

`B(6, 2) = (x_1, y_1)`

`C(2, -1) = (x_2, y_2)`

`BC = √((2 - 6)^2 + (-1 - 2)^2)`

`BC = √((-4)^2 + (-3)^2)`

`BC = √(16 + 9) = √(25)`

`BC = 5 units`