Question

What is the vertex of x^2

Answer 1

The vertex is (0,0)

Explanation:

To find the x coordinate of the vertex

x = -b/2a where ax^2 +bx +c

a=1 b=0 c=0

x = -0/2(1) = 0

The y value is found by substituting into the equation

y = (0)^2 =0

The vertex is (0,0)