Answer:
1 ± sqrt(17)
x = ---------------------------
2
Explanation:
x^2 - x - 4 =0
Using the quadratic equation
-b ± sqrt(b^2 -4ac)
x = ---------------------------
2a
Where ax^2 +bx +c
We know a =1 b = -1 c = -4
-(-1) ± sqrt((-1)^2 -4(1)(-4))
x = ---------------------------
2(1)
1 ± sqrt(1 +16)
x = ---------------------------
2
1 ± sqrt(17)
x = ---------------------------
2