Question

12

What is the equation of the line that is parallel to the
given line and passes through the point (12,-2)?
10
8
(126)
6
4
-2
o y=-x + 10
O y=-x + 12
O y=-x-10
o y=-x-12
-10-B-
B2
21
B
8
10 12 14 X
(12-2
(0.4)
10

Answer 1

y=5/6x -12

Explanation:

first find the slope of the graph

by using 2 points (0,-4) (12,6)

`m = (6 - ( - 4))/(12 - 0) = (10)/(12) = (5)/(6)`

and bcoz they r parallel they have the same slope,,now find the equation by using the given point

y-y=m(x-x)

y+2=5/6(x-12)

`y = (5)/(6) x - 12`