Answer:
a) The mean is of
![\mu = 0.16](https://img.qammunity.org/2022/formulas/mathematics/college/z5ilodrhunvwpv65b47182oiphjyb1vf01.png)
b) The standard deviation is of
![s = 0.008](https://img.qammunity.org/2022/formulas/mathematics/college/qqrg223hqbq9dc03a2u1bliszsl26vqnja.png)
Explanation:
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean
and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean
and standard deviation
![s = \sqrt{(p(1-p))/(n)}](https://img.qammunity.org/2022/formulas/mathematics/college/21siyq2l0d9z8pcii2ysmig6q1uk55fvwj.png)
Question a:
Exactly 16% of all applications were from minority members
This means
, and thus, the mean is of
![\mu = p = 0.16](https://img.qammunity.org/2022/formulas/mathematics/college/8ta326so6qjk4wqqhjzteo3xoo1dk0axx0.png)
b. Find the standard deviation of p.
2100 open positions, thus
.
![s = \sqrt{(p(1-p))/(n)}](https://img.qammunity.org/2022/formulas/mathematics/college/21siyq2l0d9z8pcii2ysmig6q1uk55fvwj.png)
![s = \sqrt{(0.16*0.84)/(2100)}](https://img.qammunity.org/2022/formulas/mathematics/college/1d0we785dc2m1m283rbgm0u6dbjbkfpt2t.png)
![s = 0.008](https://img.qammunity.org/2022/formulas/mathematics/college/qqrg223hqbq9dc03a2u1bliszsl26vqnja.png)
The standard deviation is of
![s = 0.008](https://img.qammunity.org/2022/formulas/mathematics/college/qqrg223hqbq9dc03a2u1bliszsl26vqnja.png)