Question

Divide 63(p4 + 5p3 – 24p2 ) by 9p(p + 8)​

Answer 1

We have,

\frac{63(p^4 + 5p^3 - 24p^2)}{ 9p(p + 8)}

=\frac{63p^2(p^2 + 5p - 24)}{9p(p + 8}

=\frac{7p(p^2 + 5p - 24)}{(p + 8)}

Splitting the middle term, we get

=\frac{7p(p^2 + 8p-3p - 24)}{(p + 8)}

=7p[\frac{p(p+8)-3(p+8)}{(p+8)} ]

=7p[\frac{(p+8)(p-3)}{p+8}]

=7p(p-3)

Hence the solution is 7p(p-3).

Answer 2

(21/3)p(p-3) or

(21/3)p^2 - 21p

Explanation:

63(p^4 + 5p^3 – 24p^2)/(9p(p + 8)​)

63p^2(p^2 + 5p – 24)/(9p(p + 8)​) [Factor (p^2 + 5p-24) to (p+8)(p-3)]

63p^2(p+8)(p-3))/(9p(p + 8)​) [The (p+8) terms cancel]

63p^2(p-3))/(9p) [Cancel 1 p]

63p(p-3))/(9) [Divide by 9]

(21/3)p(p-3) or

(21/3)p^2 - 21p