147k views
5 votes
A ball is thrown with an initial velocity of 70 km per second, at an angle  of 35° with the horizontal. Find the vertical and horizontal components  of the velocity.                ​

User Pbnelson
by
6.4k points

1 Answer

6 votes

Answer:

i. The horizontal component of the ball = 15.8

ii. The vertical component of the ball = 11.2

Explanation:

A thrown ball is an example of a projectile, whose motion can be explained with respect to both horizontal and vertical components.

Horizontal component of the ball = U Cos θ

Vertical component of the ball = U Sin θ

where U is the initial velocity of the ball, and θ is the angle of projection.

Thus for the given question,

U = 70 km/hr (19.44 m/s)

θ = 35°

So that;

i. The horizontal component of the ball = 19.44 Cos 35°

= 19.44 x 0.8192

= 15.785

The horizontal component of the ball = 15.8.

ii. The vertical component of the ball = 19.44 Sin 35°

= 19.44 x 0.5736

= 11.151

The vertical component of the ball = 11.2

User Nolat
by
6.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.