Answer: The voltage needed is 35.7 V
Step-by-step explanation:
Assuming that the resistors are arranged in parallel combination.
For the resistors arranged in parallel combination:
![(1)/(R)=(1)/(R_1)+(1)/(R_2)+(1)/(R_3)](https://img.qammunity.org/2022/formulas/physics/college/lb2fxf4v7ezod23gnybs9zczc1qsxfsgy4.png)
We are given:
![R_1=20\Omega\\R_2=20\Omega\\R_3=200\Omega](https://img.qammunity.org/2022/formulas/physics/college/oeuolajn94ng9fklpipjdbgp5sz7g89hm3.png)
Using above equation, we get:
![(1)/(R)=(1)/(20)+(1)/(20)+(1)/(200)\\\\(1)/(R)=(10+10+1)/(200)\\\\R=(200)/(21)=9.52\Omega](https://img.qammunity.org/2022/formulas/physics/college/ay78rheur0np1eppl9kmsjjt6e4vwz9oit.png)
Calculating the voltage by using Ohm's law:
.....(1)
where,
V = voltage applied
I = Current = 3.75 A
R = Resistance =
![9.52\Omega](https://img.qammunity.org/2022/formulas/physics/college/yz5acs6yerwx1mt5iexca7fmgarq02nhfv.png)
Putting values in equation 1, we get:
![V=3.75* 9.52\\\\V=35.7V](https://img.qammunity.org/2022/formulas/physics/college/nliy5a1d82th03g2v7uarll28ie78jsu2f.png)
Hence, the voltage needed is 35.7 V