Question

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Answer 1

Step-by-step explanation:

In the parallel combination, the equivalent resistance is given by :

`(1)/(R)=(1)/(R_1)+(1)/(R_2)+....`

4. When three 150 ohms resistors are connected in parallel, the equivalent is given by :

`(1)/(R)=(1)/(150)+(1)/(150)+(1)/(150)\\\\R=50\ \Omega`

5. Three resistors of 20 ohms, 40 ohms and 100 ohms are connected in parallel, So,

`(1)/(R)=(1)/(20)+(1)/(40)+(1)/(100)\\\\=11.76\ \Omega`

Hence, this is the required solution.