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statisticians for a roadside assistance company interviewed 50{,}00050,00050, comma, 000 randomly selected United States (US) households. Of those, 15{,}59515,59515, comma, 595 reported that they had traveled 505050 or more miles from home between December 232323 and January 444. If there are 115{,}000{,}000115,000,000115, comma, 000, comma, 000 US households, approximately how many of them do the interviews suggest traveled 505050 or more miles from home at that time

User PollusB
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Answer:

The answer is "35,868,500 people".

Step-by-step explanation:

In this question, the chance of people that have traveled above 50 miles is calculated. The chance of success is the probability.


n=50000\\\\ p=15595


\to P(x\geq 50)=(15595)/(50000)=0.3119

The population of the United States is at 1150000.

Let's determine that portion of the current population has gone more than 50 miles:


\to E(X)=np,N=115000000,p=0.3119\\\\=0.3119* 115000000\\\\=35868500

statisticians for a roadside assistance company interviewed 50{,}00050,00050, comma-example-1
User ACoolie
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