106k views
0 votes
Which statement is true about the extreme value of the given quadratic equation? y = -3x2 + 12x − 33

1 Answer

2 votes

Answer:

The equation has a maximum value with a y-coordinate of -21.

Explanation:

Given


y =-3x^2 + 12x - 33

Required

The true statement about the extreme value

First, write out the leading coefficient


Leading = -3


-3 < 0 means that the function would be a downward parabola;

Downward parabola always have their vertex on top of the parabola and as such, the function has a maximum value.

The maximum value is:


x = -(b)/(2a)

Where:


a= -3; b =12; c =-33

So, we have:


x = -(12)/(2 * -3)


x = -(12)/(-6)


x =2

Substitute
x =2 in
y =-3x^2 + 12x - 33


y = -3*2^2 + 12 * 2 - 33


y = -21

Hence, the maximum is -21.

User Makudex
by
3.4k points