Question

you are traveling in a convertible with the top down. the car is moving at a constant velocty of 25 m/s due east along falt ground. you throw a tennis ball straight upward at a speed of 15 m/swhen the ball just leaves your hand, what is the speed of the ball as measured by an observer on the side of the road

Answer 1

Teh velocity of ball with respect to the ground is 29.2 m/s.

Step-by-step explanation:

Velocity of car, vc = 25 due m/s east

velocity of ball with respect to car, v(b,c) = 15 m/s due Z axis

Write the velocities in the vector form

`\overrightarrow{v}_(c)=25 \widehat{i}\\\\\overrightarrow{v}_((b,c))=15 \widehat{k}`

The velocity of ball with respect to ground is

`\overrightarrow{v}_((b,c))= \overrightarrow{v}_((b,g))-\overrightarrow{v}_((c,g))\\\\15 \widehat{k} = \overrightarrow{v}_((b,g)) - 25 \widehat{i}\\\\\overrightarrow{v}_((b,g)) = 25 \widehat{i} + 15 \widehat{k}\\\\v_((b,g))=√(25^2 + 15^2)=29.2 m/s`