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A frame around a rectangular family portrait has a perimeter of 138 inches. The length is nine more than three times the width. Find the length and width of the frame.

User MJoy
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Given :

  • Perimeter of the frame is 138 inches.
  • The length is nine more than three times the width

To Find :

  • The Length and width of the frame .

Solution :

We know that,


\qquad{ \bold{ \pmb{2(Length + Breadth ) = Perimeter_((rectangle))}}}

Let's assume the width of the rectangle as x inches. Then the length will become (3x + 9).

Now, Substituting the given values in the formula :


\qquad \dashrightarrow{ \sf{2(3x + 9 + x )= 138}}


\qquad \dashrightarrow{ \sf{2(4x + 9 )= 138}}


\qquad \dashrightarrow{ \sf{8x + 18= 138}}


\qquad \dashrightarrow{ \sf{8x = 138 - 18}}


\qquad \dashrightarrow{ \sf{8x = 120}}


\qquad \dashrightarrow{ \sf{x = (120)/(8) }}


\qquad \dashrightarrow{ \bf \: x = 15}

Therefore,


\qquad { \pmb{ \bf{ Width _((frame)) = x = 15 \: inches}}}\:


\qquad { \pmb{ \bf{ Length _((frame)) = (3x + 9) \: = 3(15) + 9 = 54 \: inches}}}\:

User Akshay Hazari
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