Question

A merry-go-round at a playground is a circular platform that is mounted parallel to the ground and can rotate about an axis that is perpendicular to the platform at its center. The angular speed of the merry-go-round is constant, and a child at a distance of 1.4 m from the axis has a tangential speed of 2.2 m/s. What is the tangential speed of another child, who is located at a distance of 2.1 m from the axis?

(a) 1.5 m/s
(b) 3.3 m/s
(c) 2.2 m/s
(d) 5.0 m/s
(e) 0.98 m/s

Answer 1

`V_2=3.3m/s`

Step-by-step explanation:

From the question we are told that:

Distance
`d_1=1.4m`

Tangential speed
`V=2.2m/s`

Distance 2
`d_2=2.1m`

Generally the equation for Angular velocity is mathematically given by

`w=(v)/(r)`

Therefore

`(v_1)/(r_1)=(v_2)/(r_2)`

`V_2=(2.2*2.1)/(1.4)`

`V_2=3.3m/s`