What is the slope of a line perpendicular to the line passing through E(-1,6) and F(-2,-10)?

asked May 6, 2022 60.1k views

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6 votes

Answer:

Explanation:

E(-1,6) & F(-2,-10)

$Slope = (y_(2)-y_(1))/(x_(2)-x_(1))\\\\\ \ \ \ = (-10-6)/(-2-[-1])\\$

$=(-10-6)/(-2+1)\\\\=(-16)/(-1)\\\\= 16$

Slope of the line perpendicular to this line = -1/m = -1/16

SeaDrive answered May 11, 2022

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