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1 vote
A jogger moves from a position x =

4.0 m to a position of x = 16.0 m in
4.0 s. What was her average velocity?
(Unit = m/s)
Don't forget: velocities and displacements to
the right are +, to the left are -,

Please help me!

A jogger moves from a position x = 4.0 m to a position of x = 16.0 m in 4.0 s. What-example-1
User Cassim
by
4.3k points

1 Answer

6 votes

Answer:

3 m/s

Step-by-step explanation:

We'll begin by calculating the change in displacement of the jogger. This can be obtained as follow:

Initial displacement (d₁) = 4 m

Final displacement (d₂) = 16 m

Change in displacement (Δd) =?

Δd = d₂ – d₁

Δd = 16 – 4

Δd = 12 m

Finally, we shall determine the determine the average velocity. This can be obtained as follow:

Change in displacement (Δd) = 12 m

Time (t) = 4 s

Velocity (v) =?

v = Δd / t

v = 12 / 4

v = 3 m/s

Thus, the average velocity of the jogger is 3 m/s

User Michaeljt
by
3.8k points