75.4k views
0 votes
Thirty-five percent of adult Americans are regular voters. A random sample of 250 adults in a medium-size college town were surveyed, and it was found that 110 were regular voters. Estimate the true proportion of regular voters with 90% confidence and comment on your results.

User Pavel F
by
3.4k points

1 Answer

5 votes

Answer:

Hence the true proportion is (0.388, 0.492).

Explanation:

Given n=250,


p= 110/250 =0.44


a=0.1, |Z(0.05)|=1.645 (check standard normal table)

So 90% CI is


p ± Z*√[p*(1-p)/n]\\0.44 ± 1.645*sqrt(0.44*(1-0.44)/250)\\ ( 0.388, 0.492)

User Kyle Barron
by
3.9k points