Answer:
Wavelength = 0.143 m
Step-by-step explanation:
Given that,
The length of a cable, l = 48 m
Mas of the object, m = 140 jg
The tension in the cable, T = 2222 N
The frequency of the cable, f = 2 Hz
We need to find the wavelength of the resulting wave on the cable.The speed of a wave in the string is given by :
![v=\frac{\sqrt{(T)/(m/L)}}{2L}](https://img.qammunity.org/2022/formulas/physics/college/8uhfaqc964d0ohyhqpoqsp5kvzcyevr4tn.png)
Put all the values,
![v=\frac{\sqrt{(2222)/(140/48)}}{2(48)}\\\\=0.287\ m/s](https://img.qammunity.org/2022/formulas/physics/college/yny5mzlh35c1w1ml9vxohin75lwp7s4v93.png)
Let the wavelength is
. We know that,
![\lambda=(v)/(f)\\\\\lambda=(0.287)/(2)\\\\=0.143\ m](https://img.qammunity.org/2022/formulas/physics/college/ivhrlzzkfd3j1s6ilkx32zv4tsr1u8s1l7.png)
So, the wavelength of the resulting wave is 0.143 m.