Given:
distance of observer from the sound source,
![s=70~m](https://img.qammunity.org/2022/formulas/physics/high-school/wq29xl0sch67cweznqxibjck8f0p8oei6x.png)
distance between the source of image information sender and the receiver,
![d=45~miles=72420.48~m](https://img.qammunity.org/2022/formulas/physics/high-school/eadkqbhn893jya1yqyz59i3p9povie607l.png)
Assumptions:
speed of sound,
![v=343~m/s](https://img.qammunity.org/2022/formulas/physics/high-school/so6s0dyb6uvi22j7ifylyoty9ht6w4x5uf.png)
speed of the image information being sent,
(we assume it to be nearly the speed of light in vacuum)
Solution:
Time taken by the sound to reach the observer:
![time=(distance)/(speed)](https://img.qammunity.org/2022/formulas/physics/high-school/9x2035ae9qwbz3hbuehu4a967564h9m3t6.png)
![time=70/ 343](https://img.qammunity.org/2022/formulas/physics/high-school/s25xksnka9hyvlu1k05jgr7jlwmlzomj5m.png)
![time \approx 0.2~s](https://img.qammunity.org/2022/formulas/physics/high-school/xyticpdt1qabw10hid6xywsle0i6ucww24.png)
Time taken by the image to reach the destination:
![time=(72420.48)/(3* 10^8)](https://img.qammunity.org/2022/formulas/physics/high-school/zr83haeabx3xsx3px6y68np38xvr67uuxw.png)
![time=2.4* 10^(-4)~s](https://img.qammunity.org/2022/formulas/physics/high-school/t3kq4wxgi8fad004gosbv5f802x8qm6fkm.png)