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Homework Jim Thompson! Part 1

Homework Jim Thompson! Part 1-example-1
Homework Jim Thompson! Part 1-example-1
Homework Jim Thompson! Part 1-example-2

1 Answer

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Problem 1

Answers:

  • Choice A) Cylinder
  • Choice C) Rectangular prism
  • Choice D) Rectangular pyramid

Reason:

Refer the diagram below to see how rectangular cross sections are possible. The cross sections are marked in red.

For the rectangular prism, we could have a vertical or horizontal plane. For the cylinder, only a vertical cross section is possible. On the flip side, a rectangular pyramid can only have horizontal rectangular cross sections (which are similar to the base).

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Problem 2

Answer: Approximately 73,280.62908 square feet

Step-by-step explanation:

Calculate the area of the trapezoid. Ignore the small triangle for now.

A = h*(b1+b2)/2

A = 354*(266+158)/2

A = 75,048

Now calculate the area of the triangle we ignored earlier

Before we do this, we'll need to use the pythagorean theorem to find the missing horizontal piece

a^2 + b^2 = c^2

b = sqrt(c^2 - a^2)

b = sqrt(97^2 - 40^2)

b = 88.368546 which is approximate.

Now we can find the area of the small triangle

Area = base*height/2 = 88.368546*40/2 = 1,767.37092

This is to be subtracted from the area of the trapezoid we found earlier.

75,048 - 1,767.37092 = 73,280.62908

Round the result however you need to.

Homework Jim Thompson! Part 1-example-1
User Loretta
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