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7/7q+21= x /5q^2-45 then x=?​
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7/7q+21= x /5q^2-45 then x=?​

User Mohamed Nabil
by
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1 Answer

0 votes

Answer:

x = 5q - 15

Explanation:


(7)/(7q+21)=(x)/(5q^(2)-45)\\\\(7)/(7(q+3))=(x)/(5 (q^(2) -9))\\\\frac{1}{q+3}=(x)/(5*(q^(2)-3^(2)))\\\\(1)/(q+3)=(x)/(5(q+3)(q-3))\\\\(1)/(q+3)*5*(q+3)(q-3)=x\\\\5(q-3)=x\\\\x= 5q-15

User ENBYSS
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