Question

If the angle of a light ray in air is 25∘ and it enters a substance with a refracted angle of 13∘, what is the index of refraction of the substance?

A). 0.65

B). 0.53

C). 1.92

D). 1.88

Answer 1

Step-by-step explanation:

The formula for this is

`n_1sin\theta_1=n_2sin\theta_2` where the index of refraction of air is 1.00. Filling in and solving for n2:

1.00sin(25) = n₂sin(13) and

1.00(.423) = n₂(.225) and

`(1.00(.423))/(.225)=n_2` so

`n_2=1.88`, choice D.