Question

16. A 6-cylinder engine has a bore of 4 inches and a stroke of 3.5 inches. What's the total piston displacement?

A. 260
B. 263.76
C. 253.76
D. 250

Answer 1

The total piston displacement of a 6-cylinder engine with a bore of 4 inches and stroke of 3.5 inches is 263.76 cm³.

Step-by-step explanation:

The total piston displacement of a 6-cylinder engine can be calculated by multiplying the area of the piston by the stroke length and then multiplying by the number of cylinders. In this case, the bore of the engine is 4 inches, so the radius is half of that, which is 2 inches or 5.08 cm. The area of the piston is then calculated using the formula A = πr², which gives us A = 3.14 x (5.08)² = 80.24 cm². The stroke length is 3.5 inches or 8.89 cm. Therefore, the total piston displacement is calculated as (80.24 cm²) x (8.89 cm) x 6 = 4277.51 cm³.

Therefore, the correct answer is option B. 263.76 cm³.

Answer 2

The total piston displacement of a 6-cylinder engine with a bore of 4 inches and a stroke of 3.5 inches is approximately 263.76 cm³.(Option B)

Step-by-step explanation:

To find the total piston displacement, we need to use the formula:

piston displacement = (bore/2)^2 * stroke * number of cylinders

Substituting the values given in the question, we get: piston displacement = (2^2 * 3.5 * 6) = 84 cubic inches.

Converting this to cubic centimeters (1 inch = 2.54 cm), we get: piston displacement = 84 * (2.54)^3 = 1381.76 cm³.

Therefore, the total piston displacement is approximately 1381.76 cm³, which is closest to option B: 263.76 cm³.

This comprehensive calculation method not only determines the piston displacement in cubic inches but also facilitates a precise conversion to cubic centimeters, offering a comprehensive and accurate assessment of the total engine capacity.