Question

Find a formula for the quadratic function whose graph has vertex (2,4) and y-intercept -3.

Answer 1

`y=-(7)/(4)x^2+7x-3\\`

Explanation:

y - 4 = C(x - 2)²

y-intercept = -3, so x = 0, y = -3

-3 - 4 = C(2)²

so C = -7/4

`y = -(7)/(4)(x-2)^2+4=-(7)/(4)(x^2-4x+4)+4=-(7)/(4)x^2+7x-7+4\\y=-(7)/(4)x^2+7x-3\\`