205k views
4 votes
Solve 2x-5/x-2 ≤ 1

please answer fast ​

2 Answers

3 votes

Answer:

Explanation:


(2x-5)/(x-2) \leq 1\\case ~1. both ~numerator~and~denominator \geq 0\\x\\eq 2\\2x-5\leq x-2\\x\leq 3\\so~0\leq x<2U2<x\leq 3\\case~2.\\both~numerator~and~denominator<0\\2x-5\geq x-2\\x>3\\which~is~rejected~as~it~gives~both~2x-5~and ~x-2>0

User Maxsteel
by
4.0k points
3 votes

Answer:

x<=-3

Explanation:

2x-5/x-2 <= 1

Multiply both sides by x-2

2x-5<=x-2 (anything times 1 is that number.)

add 5 to both sides

2x<=x-3

subtract x from both sides

x<=-3

User Astralmaster
by
3.3k points