Question

How much work (in J) is involved in a chemical reaction if the volume decreases from 4.35 to 1.20 L against a constant pressure of 0.822 atm?

Express your answer to three significant figures and include the appropriate units.

Answer 1

W = -262 J.

Step-by-step explanation:

Hello there!

In this case, according to the given information, we can recall the definition of work in terms of constant pressure and variable volume as follows:

`W=P(V_2-V_1)`

So we plug in the given pressure and volumes to obtain:

`W=0.822atm(1.20L-4.35L)\\\\W=-2.60atm*L`

Now, we convert this number to J (Pa*m³) by using the shown below conversion factor:

`W=-2.60atm*L*(101325Pa)/(1atm) *(1m^3)/(1000L)\\\\W=-262J`

Regards!